Topic: Pari Spolter Shreds Newton and Einstein (Read 4,395 times)
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Pari Spolter Shreds Newton and Einstein « Thread Started on Apr 27, 2008, 2:35am »
Book Review
Pari Spolter in 'Gravitation Force of the Sun' exposes scientifically and mathematically the farce of Newton's Law of Universal Gravitation and Einstein's theories of relativity both general and special.
Using current and accepted scientific references Spolter shreds our current beliefs about density, mass and gravity and brings us, scientifically, to what is really going on.
And what is really going on is that we have been hoodwinked by mainstream science to believe that gravity is proportional to the quantity and density of an inert mass of a celestial body.
If you are working on a degree or expecting advancement in the scientific community do not read this book.
However if you are searching for the truth no matter what the cost and you are willing to watch proven scientific data crumble before your very eyes buy a copy of Spolters' 'Gravitational Force of the Sun' and find a nice quiet place to read.
When you finish her book and understand what she is saying I can assure you, you will never be the same. But you will know the truth.
Scientific truth will spring forth in spite of the considerable and combined efforts of the military industrial complex who consider it their sole property.
Pari Spolter will be luckier than Giordano Bruno. Bruno got burned at the stake for supporting the Copernicus idea that the earth revolved around the sun.
All that will happen to Pari is that she will be shunned, denounced, excommunicated and insulted from and by the mainstream scientific community for her efforts to publish the truth.
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Re: Pari Spolter Shreds Newton and Einstein « Reply #1 on Apr 27, 2008, 4:11am »
Thanks for the recommendation. Any particular reason you feel the need to trash other scientific doctrine to build up this person's new theory? Proclimations that she published "the truth" seems a bit overbearing. Perhaps you can share parts of the theory, proven by scientific method, that you find particularly compelling?
Any particular reason you feel the need to trash other scientific doctrine to build up this person's new theory?
Absolutely!!! Its one step closer to proving that what we have been fed about gravity is not correct... afterall we Do all know the real gravity on the moon is about .64% of Earth, right?
Any particular reason you feel the need to trash other scientific doctrine to build up this person's new theory?
Absolutely!!! Its one step closer to proving that what we have been fed about gravity is not correct... afterall we Do all know the real gravity on the moon is about .64% of Earth, right?
Isn't the usual figure quoted 1/6th the gravity of Earth?
Absolutely!!! Its one step closer to proving that what we have been fed about gravity is not correct... afterall we Do all know the real gravity on the moon is about .64% of Earth, right?
Isn't the usual figure quoted 1/6th the gravity of Earth?
Err...that was Zorgon's POINT! The Lies. The LIES that we are consistently told over and over again....
Any particular reason you feel the need to trash other scientific doctrine to build up this person's new theory?
Absolutely!!! Its one step closer to proving that what we have been fed about gravity is not correct... afterall we Do all know the real gravity on the moon is about .64% of Earth, right?
No I didn't know that. I have always understood it to be 1/6th Earth gravity. I first learned that from Sir Patrick Moore [who is probably the world's foremost expert on the Moon,] in books of his that I read over 40 years ago.
Do you have any reliable links that back your claim that it is .64% of Earth?
Joined: Apr 2008 Gender: Male Posts: 312 Location: Once Upon a Time... Karma: 21
Re: Pari Spolter Shreds Newton and Einstein « Reply #6 on May 3, 2008, 11:47pm »
Quote:
Do you have any reliable links that back your claim that it is .64% of Earth?
Hmmm what do you consider 'reliable'?
Back in the day I watched NASA show me how Astronauts would be able to do super flips and lift huge boulders... Today it is almost impossible to find those training films
Now you see the pathetic little hops when saluting the flag best they can do is 18inches Looks like 1/2 G more than 1/6 G to me
But I will throw something together for you
According to Wernher von Braun AND the Apollo 8 spacecraft actual reading...
"At a point 43,495 miles from the Moon, lunar gravity exerted a force equal to the gravity of the Earth, then some 200,000 miles distant." - Wernher von Braun (Time Magazine, July 25, 1969.)
Now the best skeptic answers we got to this were that Von Braun 'confused' metric numbers with US standard and that the meter on the space craft was 'defective'
Asked by a student looking for answers... Date: Wed Jun 10 16:59:36 1998 Posted by Mike Cottrell-Tribes Grade level: grad (science) City: Whitehorse State/Province: YT Country: Canada Area of science: Astronomy
"What is the gravitational neutral point between the Earth and the Moon? Is there empirical data from Apollo?? I can calculate it with Newton's law of Gravitation, but I wanted to know if it has been found."
Answer from.... Date: Wed Jul 8 10:41:24 1998 Posted By: David Ellis, Researcher, NASA Lewis Research Center Area of science: Astronomy
Excerpt
An accelerometer on the Apollo Command Module should have discerned the exact point where each spacecraft went through the neutral point on their journey to the Moon, but no explicit reference could be found to confirm this.
“Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning"
If the gravity were equal, the midpoint would be neutral gravity right?
Well oops on me, the calculation should be 43495/139500.
That value is 0.31
Not quite 64%, so someone help me out.
We are using the Bullialdus/Newton Law of Inverse Square.
The inverse-square law (Bullialdus/Newton) is any physical law stating that some physical quantity or strength is inversely proportional to the square of the distance between them, specifically, the gravitational attraction between two massive objects, in additional to being directly proportional to the product of their masses, is inversely proportional to the square of the distance between them.
Therefore using the following values:
Re = radius of the Earth = 3,960 miles Rm = radius of the Moon = 1,080 miles X = distance from the Earth’s center to the neutral Point = 200,000 miles Y = Distance from the Moon’s center to the neutral point = 43,495 miles Ge = Earth’s surface gravity Gm = Moons surface gravity
Since the forces of attraction of the Earth and the Moon are equal at the neutral point, the inverse-square law yields:
Ge (Re²/X²) = Gm(Rm²/Y²)
Gm/Ge = Re²Y²/Rm²X²
= (3,960)2 (43,495)2/(1,080)2 (200,000)2
= .64
Therefore, Gm = .64 Ge
So the gravity on the moon is approximately .64 that of earths gravity or almost two thirds. Now we understand why the Apollo astronauts were making those pitiful 18 inch hops on the moon. It should also be obvious why they tired so quickly.
If the moon’s gravity was in fact, one-sixth that of earth or approximately 16.66% we could work the problem in reverse and come out with a neutral point from the moon of about 24,000 miles. There is no evidence that the neutral point is that close to the moon.
That the gravity on the Moon is one sixth that of earths is one of the biggest con jobs in the history of mankind.
Current mainstream scientific thought says the Bullialdus/Newton Law of Inverse Square cannot be used in this manner without introducing the Sun as a third body in the equation. This they say would be infinitely complicated because first you would need the exact date of the measurement of the neutral point then the point of eccentricity of the moon, then the moon's cycle then the phase and finally the exact perturbation of the Sun.
Of course all of this is scientific nonsense like tidal locking. Pure, unadulterated scientific nonsense.
Joined: Apr 2008 Gender: Male Posts: 824 Location: London UK Karma: 80
Re: Pari Spolter Shreds Newton and Einstein « Reply #10 on May 8, 2008, 3:47pm »
Hi John, I hope you don't mind, but I took the liberty of enlisting the help of the "cavalry" here, and started a thread about this Lunar gravity issue over at the space.com forum here. You did say in the "Soyuz off course" thread that you had no objection:
Quote:
Help yourself. I enjoy getting crucified by the best. If I am not getting insulted I consider that I am on the wrong path.
Well, I hope there will be nothing that anyone here would consider "insulting." As far as I'm concerned, debates should always be conducted with reason and logic in any case.
The thread I started there has attracted a lot of attention, as you can probably imagine, and quite a few posts have already been made. I put a link to the thread here in my O.P. on that forum as well, so that members at both sites can read the other thread.
Do you have any reliable links that back your claim that it is .64% of Earth?
Hmmm what do you consider 'reliable'?
Back in the day I watched NASA show me how Astronauts would be able to do super flips and lift huge boulders... Today it is almost impossible to find those training films
Now you see the pathetic little hops when saluting the flag best they can do is 18inches Looks like 1/2 G more than 1/6 G to me
But I will throw something together for you
According to Wernher von Braun AND the Apollo 8 spacecraft actual reading...
"At a point 43,495 miles from the Moon, lunar gravity exerted a force equal to the gravity of the Earth, then some 200,000 miles distant." - Wernher von Braun (Time Magazine, July 25, 1969.)
Now the best skeptic answers we got to this were that Von Braun 'confused' metric numbers with US standard and that the meter on the space craft was 'defective'
Asked by a student looking for answers... Date: Wed Jun 10 16:59:36 1998 Posted by Mike Cottrell-Tribes Grade level: grad (science) City: Whitehorse State/Province: YT Country: Canada Area of science: Astronomy
"What is the gravitational neutral point between the Earth and the Moon? Is there empirical data from Apollo?? I can calculate it with Newton's law of Gravitation, but I wanted to know if it has been found."
Answer from.... Date: Wed Jul 8 10:41:24 1998 Posted By: David Ellis, Researcher, NASA Lewis Research Center Area of science: Astronomy
Excerpt
An accelerometer on the Apollo Command Module should have discerned the exact point where each spacecraft went through the neutral point on their journey to the Moon, but no explicit reference could be found to confirm this.
It appears that NASA is VERY reluctant of providing exact figures for this data, even to their own scientists
I wonder why?
Hi Zorgon. The first point I would like to make, is that there is some confusion here about the figure of ".64%." Surely you mean "64%" don't you? Especially as you queried why the astronauts could only manage "pathetic little hops." [I did wonder about this myself actually when I first read your post, but didn't query it at the time, although I should have done.] As was pointed out in the other thread [I'll quote space.com members in yellow.]:
TheOscarMP I am a little confused. Are they saying that the moon's gravity is 64% that of earth or .64%. there is a big difference
at 64% they are saying the moon's gravity is nearly 4X that of the accepted value
at .64% they are saying the moon's gravity is almost negligible (some ~26X less than the accepted value)
Also:
CalliArcale Actually, if they have fallen prey to the common (among the innumerate) mistake of calling 64% ".64%", that might go some way towards explaining why they've gotten their math so dreadfully wrong.
Regarding Wernher von Braun:
derekmcd To determine the moon's gravity, all you need to know (easier said than done) is the moon's mass and radius, and Earth's mass, radius, and gravitational force. All of which can be measured quite precisely here on earth.
The moon's mass is about 1/100th of the Earth and the radius^2 is about 1/16th that of Earth.
1/100 x 16 = .16 or about 1/6. 9.8m/s^2 / .16 = 1.56 (rounded 1.6)
I used approximations, but the result is close enough.
As for Wernher's statement he was correct. The 23,900, as shown on his graphic representation, was a point at which their paths crossed when charted on a graph neglecting the others gravity (which is not the true neutral point or L1) as seen here:
The distance from center to center is about 239,000 miles. The Lagrange point (L1... nearly identical to the neutral point) is, on average 200,000 miles from Earth's center. Thus, 39,000 miles from the Moon's center, which is about 1/6 (coincidence??). The quote of 43,495 miles might be derived from the apogee (furthest distance since the orbit of the moon is elliptical) and his 200,000 miles was, likely, just an approximation (as seen by him saying "some 200,000") for the layman.
So he basically started out with faulty information and used faulty math to give a wrong answer.
Ask him to use km next time... i hate converting.
I'll leave this post at that for now, although there are many more very good points that have been made in the other thread, which members here may wish to answer, if you read the other thread. [Just quote them, then answer would probably be best.]
I intend making further posts here, but didn't want to overload the issue by making a post that stretches from the Earth to the Moon in one go. I'm trying to keep this as simple and readable as possible, for members at both forums.
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Re: Pari Spolter Shreds Newton and Einstein « Reply #11 on May 8, 2008, 10:02pm »
Sorry I just remembered. There is one other point raised by a Space.com member, early in the thread there, that I intended to mention at this stage:
jonclarke If lunar gravity was approximately 2/3s earth's, rather than 1/6, the CSM complex would not be able to enter lunar orbit, or leave again. It would not have enough propellant. the LM would have not had enough propellant or a powerful enoughy engine to land. or, if by some miracle it did, to take off again. the same applies to all the unmanned spacecraft that entered lunar orbit or soft landed. It would require a conspiracy not just by the US but also the USSR, Japan, ESA, and China.
And why would there be a conspiracy? If the lunar graviational field was different to what was expected this would be a major discovery and celebrated as such.
Like all the lunar conspiracy stuff it is just nuts.
Sorry I just remembered. There is one other point raised by a Space.com member, early in the thread there, that I intended to mention at this stage:
jonclarke [color=yellow]If lunar gravity was approximately 2/3s earth's, rather than 1/6, the CSM complex would not be able to enter lunar orbit, or leave again. It would not have enough propellant. the LM would have not had enough propellant or a powerful enoughy engine to land. or, if by some miracle it did, to take off again. the same applies to all the unmanned spacecraft that entered lunar orbit or soft landed. It would require a conspiracy not just by the US but also the USSR, Japan, ESA, and China.
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